7n^2-14-50=7

Solution for 7n^2-14-50=7 equation:

7n^2-14-50=7

We move all terms to the left:

7n^2-14-50-(7)=0

We add all the numbers together, and all the variables

7n^2-71=0

a = 7; b = 0; c = -71;
Δ = b2-4ac
Δ = 02-4·7·(-71)
Δ = 1988
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1988}=\sqrt{4*497}=\sqrt{4}*\sqrt{497}=2\sqrt{497}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{497}}{2*7}=\frac{0-2\sqrt{497}}{14}
=-\frac{2\sqrt{497}}{14}
=-\frac{\sqrt{497}}{7}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{497}}{2*7}=\frac{0+2\sqrt{497}}{14}
=\frac{2\sqrt{497}}{14}
=\frac{\sqrt{497}}{7}
$